comments | difficulty | edit_url |
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true |
Medium |
Given a multi-dimensional array of integers, return a generator object which yields integers in the same order as inorder traversal.
A multi-dimensional array is a recursive data structure that contains both integers and other multi-dimensional arrays.
inorder traversal iterates over each array from left to right, yielding any integers it encounters or applying inorder traversal to any arrays it encounters.
Example 1:
Input: arr = [[[6]],[1,3],[]] Output: [6,1,3] Explanation: const generator = inorderTraversal(arr); generator.next().value; // 6 generator.next().value; // 1 generator.next().value; // 3 generator.next().done; // true
Example 2:
Input: arr = [] Output: [] Explanation: There are no integers so the generator doesn't yield anything.
Constraints:
0 <= arr.flat().length <= 105
0 <= arr.flat()[i] <= 105
maxNestingDepth <= 105
Can you solve this without creating a new flattened version of the array?
type MultidimensionalArray = (MultidimensionalArray | number)[];
function* inorderTraversal(arr: MultidimensionalArray): Generator<number, void, unknown> {
for (const e of arr) {
if (Array.isArray(e)) {
yield* inorderTraversal(e);
} else {
yield e;
}
}
}
/**
* const gen = inorderTraversal([1, [2, 3]]);
* gen.next().value; // 1
* gen.next().value; // 2
* gen.next().value; // 3
*/