comments | difficulty | edit_url |
---|---|---|
true |
Easy |
Given an array arr
and a function fn
, return a sorted array sortedArr
. You can assume fn
only returns numbers and those numbers determine the sort order of sortedArr
. sortedArray
must be sorted in ascending order by fn
output.
You may assume that fn
will never duplicate numbers for a given array.
Example 1:
Input: arr = [5, 4, 1, 2, 3], fn = (x) => x Output: [1, 2, 3, 4, 5] Explanation: fn simply returns the number passed to it so the array is sorted in ascending order.
Example 2:
Input: arr = [{"x": 1}, {"x": 0}, {"x": -1}], fn = (d) => d.x Output: [{"x": -1}, {"x": 0}, {"x": 1}] Explanation: fn returns the value for the "x" key. So the array is sorted based on that value.
Example 3:
Input: arr = [[3, 4], [5, 2], [10, 1]], fn = (x) => x[1] Output: [[10, 1], [5, 2], [3, 4]] Explanation: arr is sorted in ascending order by number at index=1.
Constraints:
arr
is a valid JSON arrayfn
is a function that returns a number1 <= arr.length <= 5 * 105
function sortBy(arr: any[], fn: Function): any[] {
return arr.sort((a, b) => fn(a) - fn(b));
}