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English Version

题目描述

第 i 个人的体重为 people[i],每艘船可以承载的最大重量为 limit

每艘船最多可同时载两人,但条件是这些人的重量之和最多为 limit

返回载到每一个人所需的最小船数。(保证每个人都能被船载)。

 

示例 1:

输入:people = [1,2], limit = 3
输出:1
解释:1 艘船载 (1, 2)

示例 2:

输入:people = [3,2,2,1], limit = 3
输出:3
解释:3 艘船分别载 (1, 2), (2) 和 (3)

示例 3:

输入:people = [3,5,3,4], limit = 5
输出:4
解释:4 艘船分别载 (3), (3), (4), (5)

提示:

  • 1 <= people.length <= 50000
  • 1 <= people[i] <= limit <= 30000

解法

“排序 + 双指针”实现。

Python3

class Solution:
    def numRescueBoats(self, people: List[int], limit: int) -> int:
        people.sort()
        num, i, j = 0, 0, len(people) - 1
        while i <= j:
            if people[i] + people[j] <= limit:
                i += 1
            j -= 1
            num += 1
        return num

Java

class Solution {
    public int numRescueBoats(int[] people, int limit) {
        Arrays.sort(people);
        int num = 0;
        int i = 0, j = people.length - 1;
        while (i <= j) {
            if (people[i] + people[j] <= limit) {
                ++i;
            }
            --j;
            ++num;
        }
        return num;
    }
}

...