第 i
个人的体重为 people[i]
,每艘船可以承载的最大重量为 limit
。
每艘船最多可同时载两人,但条件是这些人的重量之和最多为 limit
。
返回载到每一个人所需的最小船数。(保证每个人都能被船载)。
示例 1:
输入:people = [1,2], limit = 3 输出:1 解释:1 艘船载 (1, 2)
示例 2:
输入:people = [3,2,2,1], limit = 3 输出:3 解释:3 艘船分别载 (1, 2), (2) 和 (3)
示例 3:
输入:people = [3,5,3,4], limit = 5 输出:4 解释:4 艘船分别载 (3), (3), (4), (5)
提示:
1 <= people.length <= 50000
1 <= people[i] <= limit <= 30000
“排序 + 双指针”实现。
class Solution:
def numRescueBoats(self, people: List[int], limit: int) -> int:
people.sort()
num, i, j = 0, 0, len(people) - 1
while i <= j:
if people[i] + people[j] <= limit:
i += 1
j -= 1
num += 1
return num
class Solution {
public int numRescueBoats(int[] people, int limit) {
Arrays.sort(people);
int num = 0;
int i = 0, j = people.length - 1;
while (i <= j) {
if (people[i] + people[j] <= limit) {
++i;
}
--j;
++num;
}
return num;
}
}