院系表: Departments
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | name | varchar | +---------------+---------+ id 是该表的主键 该表包含一所大学每个院系的 id 信息
学生表: Students
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | name | varchar | | department_id | int | +---------------+---------+ id 是该表的主键 该表包含一所大学每个学生的 id 和他/她就读的院系信息
写一条 SQL 语句以查询那些所在院系不存在的学生的 id 和姓名
可以以任何顺序返回结果
下面是返回结果格式的例子
Departments 表: +------+--------------------------+ | id | name | +------+--------------------------+ | 1 | Electrical Engineering | | 7 | Computer Engineering | | 13 | Bussiness Administration | +------+--------------------------+ Students 表: +------+----------+---------------+ | id | name | department_id | +------+----------+---------------+ | 23 | Alice | 1 | | 1 | Bob | 7 | | 5 | Jennifer | 13 | | 2 | John | 14 | | 4 | Jasmine | 77 | | 3 | Steve | 74 | | 6 | Luis | 1 | | 8 | Jonathan | 7 | | 7 | Daiana | 33 | | 11 | Madelynn | 1 | +------+----------+---------------+ 结果表: +------+----------+ | id | name | +------+----------+ | 2 | John | | 7 | Daiana | | 4 | Jasmine | | 3 | Steve | +------+----------+ John, Daiana, Steve 和 Jasmine 所在的院系分别是 14, 33, 74 和 77, 其中 14, 33, 74 和 77 并不存在于院系表
外连接查询。
# Write your MySQL query statement below
SELECT
s.id, s.name
FROM
Students s
LEFT JOIN
Departments d
ON
s.department_id = d.id
WHERE
d.id IS NULL;