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1662. 检查两个字符串数组是否相等

English Version

题目描述

给你两个字符串数组 word1 和 word2 。如果两个数组表示的字符串相同，返回 true ；否则，返回 false 。

数组表示的字符串 是由数组中的所有元素 按顺序 连接形成的字符串。

 

示例 1：

输入：word1 = ["ab", "c"], word2 = ["a", "bc"]
输出：true
解释：
word1 表示的字符串为 "ab" + "c" -> "abc"
word2 表示的字符串为 "a" + "bc" -> "abc"
两个字符串相同，返回 true

示例 2：

输入：word1 = ["a", "cb"], word2 = ["ab", "c"]
输出：false

示例 3：

输入：word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
输出：true

 

提示：

• 1 <= word1.length, word2.length <= 103
• 1 <= word1[i].length, word2[i].length <= 103
• 1 <= sum(word1[i].length), sum(word2[i].length) <= 103
• word1[i] 和 word2[i] 由小写字母组成

解法

字符串拼接，比较。

Python3

class Solution:
    def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
        s1, s2 = ''.join(word1), ''.join(word2)
        return s1 == s2

Java

class Solution {
    public boolean arrayStringsAreEqual(String[] word1, String[] word2) {
        StringBuilder s1 = new StringBuilder();
        StringBuilder s2 = new StringBuilder();
        for (String word : word1) {
            s1.append(word);
        }
        for (String word : word2) {
            s2.append(word);
        }
        return Objects.equals(s1.toString(), s2.toString());
    }
}

TypeScript

function arrayStringsAreEqual(word1: string[], word2: string[]): boolean {
    let s1 = word1.join(''), s2 = word2.join('');
    return s1 == s2;
};

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