Math Parser Idea: e(value,n)

[Reptorian1125]

There are sometimes when I had to use a workaround to the fact that you cannot place variables next to e. 2.4e$var isn't allowed.

foo:
m=3
eval "2.5e$m;"

This will give a error.

So, one way of solving it is e(value,n). Which is the equivalent of {value}e{n} where value, and n is a number. Or maybe unnecessary, and there should be some fixes to the parsing of 2.5e$m.

EDIT: {value}*10^{n} will do too, but ideally I would like to see better parsing.

[dtschump]

Variable are not substituted when inside double-quotes, so you have to move them outside double quotes, like this:

foo:
  m=3
  eval "2.5e"$m";"

[Reptorian1125]

Yes, I know.

I thought it was possible with 0b, and 0x. I checked, and it turns out they only work with $1,$-1.

In Lavender Binary Map case:

		const first_binary_to_search=0b$3;
		const second_binary_to_search=0b$4;

That does work.

[dtschump]

Yes, that's because $1 is actually not a variable, it's a command argument, which is quite different (even if the syntax is similar).

• A command argument as $1 is indeed substituted inside double-quoted strings.
• A variable as $foo is not.