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fista.py
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fista.py
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"""
Module implementing the FISTA algorithm
"""
from __future__ import division, print_function
__author__ = 'Jean KOSSAIFI'
import numpy as np
import sys
from scipy.linalg import norm
from math import sqrt
from sklearn.base import BaseEstimator
from sklearn.datasets.base import Bunch
from sklearn.metrics import roc_auc_score
from hashlib import sha1
def mixed_norm(coefs, p, q=None, n_samples=None, n_kernels=None):
""" Computes the (p, q) mixed norm of the vector coefs
Parameters
----------
coefs : ndarray
a vector indexed by (l, m)
with l in range(0, n_kernels)
and m in range(0, n_samples)
p : int or np.inf
q : int or np.int
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
Returns
-------
float
"""
if q is None or p == q:
return norm(coefs, p)
else:
return norm([norm(i, p) for i in coefs.reshape(
n_kernels, n_samples)], q)
def dual_mixed_norm(coefs, n_samples, n_kernels, norm_):
""" Returns a function corresponding to the dual mixt norm
Parameters
----------
coefs : ndarray
a vector indexed by (l, m)
with l in range(0, n_kernels)
and m in range(0, n_samples)
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
norm_ : {'l11', 'l12', 'l21', 'l22'}
the dual mixed norm we want to compute
Returns
-------
float
"""
if norm_ == 'l11':
res = norm(coefs, np.inf)
elif norm_ == 'l12':
res = mixed_norm(coefs, np.inf, 2, n_samples, n_kernels)
elif norm_ == 'l21':
res = mixed_norm(coefs, 2, np.inf, n_samples, n_kernels)
else:
res = norm(coefs, 2)
return res
def by_kernel_norm(coefs, p, q, n_samples, n_kernels):
""" Computes the (p, q) norm of coefs for each kernel
Parameters
----------
coefs : ndarray
a vector indexed by (l, m)
with l in range(0, n_kernels)
and m in range(0, n_samples)
p : int or np.inf
q : int or np.inf
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
Returns
-------
A list of the norms of the sub vectors associated to each kernel
"""
return [mixed_norm(i, p, q, n_samples, 1)
for i in coefs.reshape(n_kernels, n_samples)]
def prox_l11(u, lambda_):
""" Proximity operator for l(1, 1, 2) norm
:math:`\\hat{\\alpha}_{l,m} = sign(u_{l,m})\\left||u_{l,m}| - \\lambda \\right|_+`
Parameters
----------
u : ndarray
The vector (of the n-dimensional space) on witch we want
to compute the proximal operator
lambda_ : float
regularisation parameter
Returns
-------
ndarray : the vector corresponding to the application of the
proximity operator to u
"""
return np.sign(u) * np.maximum(np.abs(u) - lambda_, 0.)
def prox_l22(u, lambda_):
""" proximity operator l(2, 2, 2) norm
Parameters
----------
u : ndarray
The vector (of the n-dimensional space) on witch we want to compute the proximal operator
lambda_ : float
regularisation parameter
Returns
-------
ndarray : the vector corresponding to the application of the proximity operator to u
Notes
-----
:math:`\\hat{\\alpha}_{l,m} = \\frac{1}{1 + \\lambda} \\, u_{l,m}`
"""
return 1./(1.+lambda_)*u
def prox_l21_1(u, l, n_samples, n_kernels):
""" Proximity operator l(2, 1, 1) norm
Parameters
----------
u : ndarray
The vector (of the n-dimensional space) on witch we want to compute the proximal operator
lambda_ : float
regularisation parameter
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
Returns
-------
ndarray : the vector corresponding to the application of the proximity operator to u
Notes
-----
.. math::
\hat{\alpha}_{l,m} = u_{l,m} \left| 1 - \frac{\lambda}{\|u_{l \bullet}\|_{2}} \right|_+\
where l is in range(0, n_samples) and m is in range(0, n_kernels)
so :math:`u_{l\\bullet}` = [u(l, m) for m in n_kernels]
"""
return (u.reshape(n_kernels, n_samples) *\
[max(1. - l/norm(u[np.arange(n_kernels)*n_samples+i], 2), 0.)
for i in range(n_samples)]).reshape(-1)
def prox_l21(u, l, n_samples, n_kernels):
""" proximity operator l(2, 1, 2) norm
Parameters
----------
u : ndarray
The vector (of the n-dimensional space) on witch we want to compute the proximal operator
lambda_ : float
regularisation parameter
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
Returns
-------
ndarray : the vector corresponding to the application of the proximity operator to u
Notes
-----
:math:`\\hat{\\alpha}_{l,m} = u_{l,m} \\left| 1 - \\frac{ \\lambda}{ \\|u_{l \\bullet }\\|_{2}} \\right|_+`
where l is in range(0, n_kernels) and m is in range(0, n_samples)
so :math:`u_{l \\bullet }` = [u(l, m) for l in n_samples]
"""
for i in u.reshape(n_kernels, n_samples):
n = norm(i, 2)
if n==0 or n==np.Inf:
i[:] = 0
else:
i[:] *= max(1. - l/n, 0.)
# !! If you do just i *= , u isn't modified
# The slice is needed here so that the array can be modified
return u
def prox_l12(u, l, n_samples, n_kernels):
""" proximity operator for l(1, 2, 2) norm
Parameters
----------
u : ndarray
The vector (of the n-dimensional space) on witch we want to compute the proximal operator
lambda_ : float
regularisation parameter
n_samples : int, optional
number of elements in each kernel
default is None
n_kernels : int, optional
number of kernels
default is None
Returns
-------
ndarray : the vector corresponding to the application of the proximity operator to u
Notes
-----
:math:`\\hat{\\alpha}_{l,m} = sign(u_{l,m})\\left||u_{l,m}| - \\frac{\\lambda \\sum\\limits_{m_l=1}^{M_l} u2_{l,m_l}}{(1+\\lambda M_l) \\|u_{l \\bullet }\\|_{2}} \\right|_+`
where :math:`u2_{l,m_l}` denotes the :math:`|u_{l,m_l}|`
ordered by descending order for fixed :math:`l`, and the
quantity :math:`M_l` is the number computed in compute_M
"""
for i in u.reshape(n_kernels, n_samples):
Ml, sum_Ml = compute_M(i, l, n_samples)
# i[:] so that u is really modified
n = norm(i, 2)
if n == 0 or n == np.Inf:
i[:] = 0
else:
i[:] = np.sign(i)*np.maximum(
np.abs(i)-(l*sum_Ml)/((1.+l*Ml)*n), 0.)
return u
def compute_M(u, lambda_, n_samples):
"""
Parameters
----------
u : ndarray
ndarray of size (n_samples * n_samples) representing a subvector of K,
ie the samples for a single kernel
lambda_ : int
n_samples : int
number of elements in each kernel
ie number of elements of u
Notes
-----
:math:`M_l` is the number such that
:math:`u2_{l,M_l+1} \\leq \\lambda \\sum_{m_l=1}^{M_l+1} \\left( u2_{l,m_l} - u2_{l,M_l+1}\\right)`
and
:math:`u2_{l,M_l} > \\lambda\\sum_{m_l=1}^{M_l} \\left( u2_{l,m_l} - u2_{k,M_l}\\right)`
Detailed explication
let u denotes |u(l)|, the vector associated with the kernel l, ordered by descending order
Ml is the integer such that
u(Ml) <= l * sum(k=1..Ml + 1) (u(k) - u(Ml + 1)) (S1)
and
u(Ml) > l * sum(k=1..Ml) (u(k) - u(Ml) (S2)
Note that in that definition, Ml is in [1..Ml]
In python, while Ml is in [1..(Ml-1)], indices will be in [0..(Ml-1)], so we must take care of indices.
That's why, we consider Ml is in [0..(Ml-1)] and, at the end, we add 1 to the result
Detailed example
if u(l) = [0 1 2 3] corrsponds to the vector associated with a kernel
then u = |u(l)| ordered by descending order ie u = [3 2 1 0]
Then u = [3 2 1 0]
let l = 1
Ml is in {0, 1, 2} (not 3 because we also consider Ml+1)
# Note : in fact Ml is in {1, 2, 3} but it is more convenient
# to consider it is in {0, 1, 2} as indexing in python starts at 0
# We juste have to add 1 to the final result
if Ml = 0 then S1 = 1 and S2 = 0
if Ml = 1 then S1 = 3 and S2 = 1
if Ml = 2 then S1 = 6 and S2 = 3
if Ml = 0 then u(Ml+1)=u(1)=2 > l*... =1 (S1 is not verified)
and u(Ml)=u(0)=3 > l*... =0 (S2 is verified)
if Ml = 1 then u(Ml+1)=u(2)=1 <= l*... =3 (S1 is verified)
and u(Ml)=u(1)=2 > l*... =1 (S2 is verified)
if Ml = 2 then u(Ml+1)=u(3)=0 <= l*... =6 (S1 is verified)
but u(Ml)=u(2)=1 <= l*... =3 (S1 is not verified)
Conclusion : Ml = 1 + 1 !!
Ml = 2 because in python, indexing starts at 0, so Ml +1
"""
u = np.sort(np.abs(u))[::-1]
S1 = u[1:] - lambda_*(np.cumsum(u)[:-1] - (np.arange(n_samples-1)+1)*u[1:])
S2 = u[:-1] - lambda_*(np.cumsum(u)[:-1] - (np.arange(n_samples-1)+1)*u[:-1])
Ml = np.argmax((S1<=0.) & (S2>0.)) + 1
return Ml, np.sum(u[:Ml]) # u[:Ml] = u[0, 1, ..., Ml-1] !!
def hinge_step(y, K, Z):
"""
Returns the point in witch we apply gradient descent
parameters
----------
y : np-array
the labels vector
K : 2D np-array
the concatenation of all the kernels, of shape
n_samples, n_kernels*n_samples
Z : a linear combination of the last two coefficient vectors
returns
-------
res : np-array of shape n_samples*,_kernels
a point of the space where we will apply gradient descent
"""
return np.dot(K.transpose(), np.maximum(1 - np.dot(K, Z), 0))
def least_square_step(y, K, Z):
"""
Returns the point in witch we apply gradient descent
parameters
----------
y : np-array
the labels vector
K : 2D np-array
the concatenation of all the kernels, of shape
n_samples, n_kernels*n_samples
Z : a linear combination of the last two coefficient vectors
returns
-------
res : np-array of shape n_samples*,_kernels
a point of the space where we will apply gradient descent
"""
return np.dot(K.transpose(), y - np.dot(K,Z))
def _load_Lipschitz_constant(K):
""" Loads the Lipschitz constant and computes it if not already saved
Parameters
----------
K : 2D-ndarray
The matrix of witch we want to compute the Lipschitz constant
Returns
-------
float
Notes
-----
Lipshitz constant is just a number < 2/norm(np.dot(K, K.T), 2)
The constant is stored in a npy hidden file, in the current directory.
The filename is the sha1 hash of the ndarray
"""
try:
mu = np.load('./.%s.npy' % sha1(K).hexdigest())
except:
mu = 1/norm(np.dot(K, K.transpose()), 2)
np.save('./.%s.npy' % sha1(K).hexdigest(), mu)
return mu
class Fista(BaseEstimator):
"""
Fast iterative shrinkage/thresholding Algorithm
Parameters
----------
lambda_ : int, optionnal
regularisation parameter
default is 0.5
loss : {'squared-hinge', 'least-square'}, optionnal
the loss function to use
defautl is 'squared-hinge'
penalty : {'l11', 'l22', 'l12', 'l21'}, optionnal
norm to use as penalty
default is l11
n_iter : int, optionnal
number of iterations
default is 1000
recompute_Lipschitz_constant : bool, optionnal
if True, the Lipschitz constant is recomputed everytime
if False, it is stored based on it's sha1 hash
default is False
"""
def __init__(self, lambda_=0.5, loss='squared-hinge', penalty='l11', n_iter=1000, recompute_Lipschitz_constant=False):
self.n_iter = n_iter
self.lambda_ = lambda_
self.loss = loss
self.penalty = penalty
self.p = int(penalty[1])
self.q = int(penalty[2])
self.recompute_Lipschitz_constant = recompute_Lipschitz_constant
def fit(self, K, y, Lipschitz_constant=None, verbose=0, **params):
""" Fits the estimator
We want to solve a problem of the form y = KB + b
where K is a (n_samples, n_kernels*n_samples) matrix.
Parameters
---------
K : ndarray
numpy array of shape (n, p)
K is the concatenation of the p/n kernels
where each kernel is of size (n, n)
y : ndarray
an array of the labels to predict for each kernel
y is of size p
where K.shape : (n, p)
Lipschitz_constant : float, optionnal
allow the user to pre-compute the Lipschitz constant
(its computation can be very slow, so that parameter is very
usefull if you were to use several times the algorithm on the same data)
verbose : {0, 1}, optionnal
verbosity of the method : 1 will display informations while 0 will display nothing
default = 0
Returns
-------
self
"""
next_step = hinge_step
if self.loss=='squared-hinge':
K = y[:, np.newaxis] * K
# Equivalent to K = np.dot(np.diag(y), X) but faster
elif self.loss=='least-square':
next_step = least_square_step
(n_samples, n_features) = K.shape
n_kernels = int(n_features/n_samples) # We assume each kernel is a square matrix
self.n_samples, self.n_kernels = n_samples, n_kernels
if Lipschitz_constant==None:
Lipschitz_constant = _load_Lipschitz_constant(K)
tol = 10**(-6)
coefs_current = np.zeros(n_features, dtype=np.float) # coefficients to compute
coefs_next = np.zeros(n_features, dtype=np.float)
Z = np.copy(coefs_next) # a linear combination of the coefficients of the 2 last iterations
tau_1 = 1
if self.penalty=='l11':
prox = lambda u:prox_l11(u, self.lambda_*Lipschitz_constant)
elif self.penalty=='l22':
prox = lambda u:prox_l22(u, self.lambda_*Lipschitz_constant)
elif self.penalty=='l21':
prox = lambda u:prox_l21(u, self.lambda_*Lipschitz_constant, n_samples, n_kernels)
elif self.penalty=='l12':
prox = lambda u:prox_l12(u, self.lambda_*Lipschitz_constant, n_samples, n_kernels)
if verbose==1:
self.iteration_dual_gap = list()
for i in range(self.n_iter):
coefs_current = coefs_next # B_(k-1) = B_(k)
coefs_next = prox(Z + Lipschitz_constant*next_step(y, K, Z))
tau_0 = tau_1 #tau_(k+1) = tau_k
tau_1 = (1 + sqrt(1 + 4*tau_0**2))/2
Z = coefs_next + (tau_0 - 1)/tau_1*(coefs_next - coefs_current)
# Dual problem
objective_var = 1 - np.dot(K, coefs_next)
objective_var = np.maximum(objective_var, 0) # Shrink
# Primal objective function
penalisation = self.lambda_/self.q*(mixed_norm(coefs_next,
self.p, self.q, n_samples, n_kernels)**self.q)
loss = 0.5*np.sum(objective_var**2)
objective_function = penalisation + loss
# Dual objective function
dual_var = objective_var
if self.lambda_ != 0:
dual_penalisation = dual_mixed_norm(np.dot(K.T,dual_var)/self.lambda_,
n_samples, n_kernels, self.penalty)
if self.q==1:
# Fenchel conjugate of a mixed norm
if dual_penalisation > 1:
dual_var = dual_var / dual_penalisation
# If we did not normalise, dual_penalisation
# would be +infinity ...
dual_penalisation = 0
else:
# Fenchel conjugate of a squared mixed norm
dual_penalisation = self.lambda_/2*(dual_penalisation**2)
else:
dual_penalisation = 0
dual_loss = -0.5*np.sum(dual_var**2) + np.sum(dual_var)
# trace(np.dot(duat_var[:, np.newaxis], y)) au lieu du sum(dual_var) ?
dual_objective_function = dual_loss - self.lambda_/self.q*dual_penalisation
gap = abs(objective_function - dual_objective_function)
if verbose:
sys.stderr.write("Iteration : %d\r" % i )
# print "iteration %d" % i
self.iteration_dual_gap.append(gap)
if i%1000 == 0:
print("primal objective : %f, dual objective : %f, dual_gap : %f" % (objective_function, dual_objective_function, gap))
if gap<=tol and i>10:
print("convergence at iteration : %d" %i)
break
if verbose:
print("dual gap : %f" % gap)
print("objective_function : %f" % objective_function)
print("dual_objective_function : %f" % dual_objective_function)
print("dual_penalisation : %f" % dual_penalisation)
print("dual_loss : %f" % dual_loss)
self.coefs_ = coefs_next
self.gap = gap
self.objective_function = objective_function
self.dual_objective_function = dual_objective_function
return self
def predict(self, K):
""" Returns the prediction associated to the Kernels represented by K
Parameters
----------
K : ndarray
ndarray of size (n_samples, n_kernels*n_samples) representing the kernels
Returns
-------
ndarray : the prediction associated to K
"""
if self.loss=='squared-hinge':
res = np.sign(np.dot(K, self.coefs_))
res[res==0] = 1
return res
else:
return np.dot(K, self.coefs_)
def score(self, K, y):
""" Returns the score prediction for the given data
Parameters
----------
K : ndarray
matrix of observations
y : ndarray
the labels correspondings to K
Returns
-------
The percentage of good classification for K
"""
if self.loss=='squared-hinge':
return np.sum(np.equal(self.predict(K), y))*100./len(y)
else:
print("Score not yet implemented for regression\n")
return None
def info(self, K, y):
""" For test purpose
Parameters
----------
K : 2D-array
kernels
y : ndarray
labels
Returns
-------
A dict of informations
"""
result = Bunch()
n_samples, n_kernels = self.n_samples, self.n_kernels
nulled_kernels = 0
nulled_coefs_per_kernel = list()
for i in self.coefs_.reshape(n_kernels, n_samples):
if len(i[i!=0]) == 0:
nulled_kernels = nulled_kernels + 1
nulled_coefs_per_kernel.append(len(i[i==0]))
result['score'] = self.score(K, y)
result['norms'] = by_kernel_norm(self.coefs_, self.p, self.q,
n_samples, n_kernels)
result['nulled_coefs'] = len(self.coefs_[self.coefs_==0])
result['nulled_kernels'] = nulled_kernels
result['nulled_coefs_per_kernel'] = nulled_coefs_per_kernel
result['objective_function'] = self.objective_function
result['dual_objective_function'] = self.dual_objective_function
result['gap'] = self.gap
result['auc_score'] = roc_auc_score(y, self.predict(K))
result['lambda_'] = self.lambda_
return result