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when I throw an exception in the labmda expression of hgetall, it goes to line 70 (in the file thread_pool.cpp).
Continue debugging, programm will pause when excute to line 124 (in the file thread_pool.cpp).
So, how can i get the exception out of the lambda expression?
platform: Windows10, VS2019-16.7.5
Thank you!
The text was updated successfully, but these errors were encountered:
code:
when I throw an exception in the labmda expression of hgetall, it goes to line 70 (in the file thread_pool.cpp).
Continue debugging, programm will pause when excute to line 124 (in the file thread_pool.cpp).
So, how can i get the exception out of the lambda expression?
platform: Windows10, VS2019-16.7.5
Thank you!
The text was updated successfully, but these errors were encountered: