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Using a function invocation in a binary expression causes an attempt to implicit cast #14

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dlurton opened this issue Nov 6, 2017 · 0 comments
Open

Using a function invocation in a binary expression causes an attempt to implicit cast #14

dlurton opened this issue Nov 6, 2017 · 0 comments

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@dlurton
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dlurton commented Nov 6, 2017

...the result of the function call which of course results in a debug assertion failure because we can't cast
void to anything.

func foo::void() 123
assert(123 == foo())
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@dlurton