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Let $a$ be a square-free positive integer (square-free means for all $k\in \Z$ if $k^2|a$, then $k=\pm 1$). Let $p_1,\dots,p_n$ be primes such that $a=p_1p_2\cdots p_n$. Prove that the number of divisors of $a$ is $2^n$.
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Let $a$ be a positive integer, and let $p_1,\dots,p_n$ be distinct primes such that $a=p_1^{a_1}p_2^{a_2}\cdots p_n^{a_n}$. Prove that the number of divisors of $a$ is $\prod_{i=1}^n(a_i+1)$.