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day17.rs
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day17.rs
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//! # Clumsy Crucible
//!
//! Our high level approach is an [A*](https://en.wikipedia.org/wiki/A*_search_algorithm) search.
//! This [fantastic blog](https://www.redblobgames.com/pathfinding/a-star/introduction.html)
//! is a great introduction to this algorithm.
//!
//! The heuristic is the [Manhattan distance](https://en.wikipedia.org/wiki/Taxicab_geometry)
//! to the bottom right corner. This will never overestimate the actual distance which is an
//! essential characteristic in the heuristic.
//!
//! A crucial insight speeds things up. We only needs to store `(position, direction)` pairs in
//! the map of previously seen costs and do not also need to store the number of steps.
//! The reason is that each time we generate new states from the current state we loop over all
//! possible forward states. This implicitly means that every new state will always make a left or
//! right turn, alternating between horizontal and vertical movements.
//!
//! It's a little more subtle but we also don't need to store 4 directions but only 2, horizontal
//! and vertical. The reason is similar to not encoding the number of steps. As we are always
//! implictly going to make a left or right turn immediately, entering a square from the opposite
//! direction is equivalent. This reduces the storage space and time by half.
//!
//! To speed things up even further we use a trick. Classic A* uses a generic priority queue that
//! can be implemented in Rust using a [`BinaryHeap`]. However the total cost follows a strictly
//! increasing order in a constrained range of values, so we can use a much faster
//! [bucket queue](https://en.wikipedia.org/wiki/Bucket_queue). The maximum possible increase in
//! heuristic is 10 * 9 from heat plus 10 for the distance change for a total of 100 buckets.
//!
//! [`BinaryHeap`]: std::collections::BinaryHeap
use crate::util::grid::*;
use crate::util::parse::*;
/// Parse the input into a 2D grid of `u8` then convert to `u32` for convenience.
pub fn parse(input: &str) -> Grid<i32> {
let Grid { width, height, bytes } = Grid::parse(input);
let bytes = bytes.iter().map(|b| b.to_decimal() as i32).collect();
Grid { width, height, bytes }
}
/// Search with a maximum of 3 steps in any direction.
pub fn part1(grid: &Grid<i32>) -> i32 {
astar::<1, 3>(grid)
}
/// Search with a minimum of 4 and maximum of 10 steps in any direction. Using const generics
/// to specify the limits allows the compiler to optimize and unroll loops, speeding things
/// up by about 25%, versus specifying the loop limits as regular parameters.
pub fn part2(grid: &Grid<i32>) -> i32 {
astar::<4, 10>(grid)
}
/// Optimized A* search.
fn astar<const L: i32, const U: i32>(grid: &Grid<i32>) -> i32 {
let size = grid.width;
let stride = size as usize;
let heat = &grid.bytes;
let mut index = 0;
let mut todo = (0..100).map(|_| Vec::with_capacity(1000)).collect::<Vec<_>>();
let mut cost = vec![[i32::MAX; 2]; heat.len()];
// Start from the top left corner checking both vertical and horizontal directions.
todo[0].push((0, 0, 0));
todo[0].push((0, 0, 1));
cost[0][0] = 0;
cost[0][1] = 0;
loop {
// All items in the same bucket have the same priority.
while let Some((x, y, direction)) = todo[index % 100].pop() {
// Retrieve cost for our current location and direction.
let index = (size * y + x) as usize;
let steps = cost[index][direction];
// The heuristic is used as an index into the bucket priority queue.
// Prefer heading towards the bottom right corner, except if we're in the top left
// quadrant where all directions are considered equally. This prevents a pathological
// dual frontier on some inputs that takes twice the time.
let heuristic = |x: i32, y: i32, cost: i32| {
let priority = (2 * size - x - y).min(size + size / 2);
((cost + priority) % 100) as usize
};
// Check if we've reached the end.
if x == size - 1 && y == size - 1 {
return steps;
}
// Alternate directions each turn. We arbitrarily pick `0` to mean vertical and `1` to
// mean horizontal. These constants are used as offsets into the `cost` array.
if direction == 0 {
// We just moved vertically so now check both left and right directions.
// Each direction loop is the same:
// * Check to see if we gone out of bounds
// * Increase the cost by the "heat" of the square we've just moved into.
// * Check if we've already been to this location with a lower cost.
// * Add new state to priority queue.
// Right
let mut next = index;
let mut extra = steps;
for i in 1..=U {
if x + i >= size {
break;
}
next += 1;
extra += heat[next];
if i >= L && extra < cost[next][1] {
todo[heuristic(x + i, y, extra)].push((x + i, y, 1));
cost[next][1] = extra;
}
}
// Left
let mut next = index;
let mut extra = steps;
for i in 1..=U {
if i > x {
break;
}
next -= 1;
extra += heat[next];
if i >= L && extra < cost[next][1] {
todo[heuristic(x - i, y, extra)].push((x - i, y, 1));
cost[next][1] = extra;
}
}
} else {
// We just moved horizontally so now check both up and down directions.
// Down
let mut next = index;
let mut extra = steps;
for i in 1..=U {
if y + i >= size {
break;
}
next += stride;
extra += heat[next];
if i >= L && extra < cost[next][0] {
todo[heuristic(x, y + i, extra)].push((x, y + i, 0));
cost[next][0] = extra;
}
}
// Up
let mut next = index;
let mut extra = steps;
for i in 1..=U {
if i > y {
break;
}
next -= stride;
extra += heat[next];
if i >= L && extra < cost[next][0] {
todo[heuristic(x, y - i, extra)].push((x, y - i, 0));
cost[next][0] = extra;
}
}
}
}
// Bump priority by one to check the next bucket.
index += 1;
}
}