How do you override the output directory in the command line?

[Vurv78]

Looking to get the contents of it through another program that will automatically invoke premake on unknown github repos.

[samsinsane]

Your question is pretty vague and could be interpreted many different ways.

• Command line arguments
• newoption
• location?
• targetdir?

[samsinsane]

Read the Command line arguments link provided, it will show you how to use the _OPTIONS table as well as how to create your own command line options.

[Vurv78]

I'm not in control of what these premake scripts contain. So I have no idea if they will use _OPTIONS/newoption or not nor can I make my own options.

Trying to get the same output location for files like these which are completely different

https://github.com/danielga/gm_sourcenet/blob/master/premake5.lua
https://github.com/SuperiorServers/gm_tmysql4/blob/master/projects/premake5.lua
https://github.com/viral32111/gm_uuid/blob/master/scripts/premake5.lua

I can do this in cmake with -B\dir\here\ for example

[samsinsane]

Premake doesn't currently support that. I'm not sure if there's a reason for that or not, @starkos might be able to shed some light on this? I would imagine that numerous APIs that contain paths relative to the output location would break - such as postbuildcommands and friends.

[starkos]

Yup, that's exactly why we leave support for relocatable targets up to the script authors. But you can always wrap the project's script in one of your own, and then apply your own settings, something like…

dofile('some_project/premake5.lua')

project('SomeProject')
   location 'some/other/location'

Which can then use command line options or whatever else you like to set the location. Does that help?

[Vurv78]

Yeah that sounds good! Thanks you both, sorry for my initial vague question