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03 -- `data.frame` continued |
Let's start with a clean working directory. Create the folder data/
within
your working directory, and download the 2 datasets:
download.file("http://r-bio.github.io/data/surveys.csv",
"data/surveys.csv")
download.file("http://r-bio.github.io/data/species.csv",
"data/species.csv")
and then check that you can load the surveys dataset (for now) into R:
## X record_id month day year plot species_id sex wgt
## 1 1 1 7 16 1977 2 NL M NA
## 2 2 2 7 16 1977 3 NL M NA
## 3 3 3 7 16 1977 2 DM F NA
## 4 4 4 7 16 1977 7 DM M NA
## 5 5 5 7 16 1977 3 DM M NA
## 6 6 6 7 16 1977 1 PF M NA
## 'data.frame': 35549 obs. of 9 variables:
## $ X : int 1 2 3 4 5 6 7 8 9 10 ...
## $ record_id : int 1 2 3 4 5 6 7 8 9 10 ...
## $ month : int 7 7 7 7 7 7 7 7 7 7 ...
## $ day : int 16 16 16 16 16 16 16 16 16 16 ...
## $ year : int 1977 1977 1977 1977 1977 1977 1977 1977 1977 1977 ...
## $ plot : int 2 3 2 7 3 1 2 1 1 6 ...
## $ species_id: chr "NL" "NL" "DM" "DM" ...
## $ sex : chr "M" "M" "F" "M" ...
## $ wgt : int NA NA NA NA NA NA NA NA NA NA ...
data.frame
is the de facto data structure for most tabular data and what we
use for statistics and plotting.
A data.frame
is a collection of vectors of identical lengths. Each vector
represents a column, and each vector can be of a different class (e.g.,
characters, integers, factors). The str()
function is useful to inspect the
data types of the columns.
The most common way you are going to create data.frame
objects is when you
will use the functions read.csv()
or read.table()
, in other words, when
importing spreadsheets from your hard drive (or the web).
You can also create data.frame
manually with the function data.frame()
. This
function can also take the argument stringsAsFactors
. Compare the output of
these examples:
example_data <- data.frame(animal=c("dog", "cat", "sea cucumber", "sea urchin"),
feel=c("furry", "furry", "squishy", "spiny"),
weight=c(45, 8, 1.1, 0.8))
str(example_data)
## 'data.frame': 4 obs. of 3 variables:
## $ animal: Factor w/ 4 levels "cat","dog","sea cucumber",..: 2 1 3 4
## $ feel : Factor w/ 3 levels "furry","spiny",..: 1 1 3 2
## $ weight: num 45 8 1.1 0.8
Here you can observe the default behavior of the data.frame
function. The
columns animal
and feel
are of class factor
. By default, data.frame
converts (= coerces) columns that contain characters (i.e., text) into a vector
of class factor
. Depending on what you want to do with the data, you may want
to keep these columns as character
. To do so, read.csv()
and read.table()
have an argument called stringsAsFactors
which can be set to FALSE
:
example_data <- data.frame(animal=c("dog", "cat", "sea cucumber", "sea urchin"),
feel=c("furry", "furry", "squishy", "spiny"),
weight=c(45, 8, 1.1, 0.8), stringsAsFactors=FALSE)
str(example_data)
## 'data.frame': 4 obs. of 3 variables:
## $ animal: chr "dog" "cat" "sea cucumber" "sea urchin"
## $ feel : chr "furry" "furry" "squishy" "spiny"
## $ weight: num 45 8 1.1 0.8
If you want to manually change the class of one of the column, you can use the
function as.factor()
(below we'll cover in more detail how to work with
columns):
example_data$feel <- as.factor(example_data$feel)
str(example_data)
## 'data.frame': 4 obs. of 3 variables:
## $ animal: chr "dog" "cat" "sea cucumber" "sea urchin"
## $ feel : Factor w/ 3 levels "furry","spiny",..: 1 1 3 2
## $ weight: num 45 8 1.1 0.8
- There are a few mistakes in this hand crafted
data.frame
, can you spot and fix them? Don't hesitate to experiment!
author_book <- data.frame(author_first=c("Charles", "Ernst", "Theodosius"),
author_last=c(Darwin, Mayr, Dobzhansky),
year=c(1942, 1970))
- Can you predict the class for each of the columns in the following example?
Check your guesses using
str(country_climate)
. Are they what you expected? Why? why not?
country_climate <- data.frame(country=c("Canada", "Panama", "South Africa", "Australia"),
climate=c("cold", "hot", "temperate", "hot/temperate"),
temperature=c(10, 30, 18, "15"),
north_hemisphere=c(TRUE, TRUE, FALSE, "FALSE"),
has_kangaroo=c(FALSE, FALSE, FALSE, 1))
Check your guesses using str(country_climate)
. Are they what you expected?
Why? why not?
R coerces (when possible) to the data type that is the least common denominator and the easiest to coerce to. You can review the notes from the second lecture to review the coercion rules R uses.
We already saw how the functions head()
and str()
can be useful to check the
content and the structure of a data.frame
. Here is a non-exhaustive list of
functions to get a sense of the content/structure of the data.
- Size:
dim()
- returns a vector with the number of rows in the first element, and the number of columns as the second element (the __dim__ensions of the object)nrow()
- returns the number of rowsncol()
- returns the number of columns
- Content:
head()
- shows the first 6 rowstail()
- shows the last 6 rows
- Names:
names()
- returns the column names (synonym ofcolnames()
fordata.frame
objects)rownames()
- returns the row names
- Summary:
str()
- structure of the object and information about the class, length and content of each columnsummary()
- summary statistics for each column
Note: most of these functions are "generic", they can be used on other types of
objects besides data.frame
.
Use these functions on the surveys
data set loaded in R.
Our survey data frame has rows and columns (it's a 2-dimensional object), if we want to extract some specific data from it (a slice of it), we need to specify the "coordinates" we want the data to come from. To do this, we use the square bracket notation (just like with vectors), except that we need to add a comma to indicate the rows and columns we want. Row numbers come first, followed by column numbers. Here are some examples:
surveys[1, 1] # first element in the first column of the data frame
surveys[1, 6] # first element in the 6th column
surveys[1:3, 7] # first three elements in the 7th column
surveys[3, ] # the 3rd element for all columns
surveys[, 8] # the entire 8th column
head_surveys <- surveys[1:6, ] # surveys[1:6, ] is equivalent to head(surveys)
- The function
nrow()
on adata.frame
returns the number of rows. Use it, in conjuction withseq()
to create a newdata.frame
calledsurveys_by_10
that includes every 10th row of the survey data frame starting at row 10 (10, 20, 30, ...)
In particular for larger datasets, it can be tricky to remember the column
number that corresponds to a particular variable (Are species names in column 6
or 8? oh, right... they are in column 7), and using the column number to extract
the data (i.e., surveys[, 7]
) may not be practical. In some cases, in which
column the variable will be can change if the script you are using adds or
removes columns. It's therefore often better to use column names to refer to a
particular variable, and it makes your code easier to read and your intentions
clearer.
You can do operations on a particular column, by selecting it using the $
sign. In this case, the entire column is a vector. For instance, to extract all
the weights from our datasets, we can use: surveys$wgt
. You can use
names(surveys)
or colnames(surveys)
to remind yourself of the column names.
In some cases, you may way to select more than one column. You can do this using
the square brackets: surveys[, c("wgt", "sex")]
.
When analyzing data, though, we often want to look at partial statistics, such as the maximum value of a variable per species or the average value per plot.
One way to do this is to select the data we want, and create a new temporary
array, using the subset()
function. For instance, if we just want to look at
the animals of the species "DO":
surveys_DO <- subset(surveys, species == "DO")
-
What does the following do (Try to guess without executing it)?
surveys_DO$month[2] <- 8
-
Use the function
subset
to create adata.frame
that contains all individuals of the species "DM" that were collected in 2002. How many individuals of the species "DM" were collected in 2002?
Sometimes, you may have to add a new column to your dataset that represents a
new variable. You can add columns to a data.frame
using the function cbind()
(__c__olumn bind). Beware, the additional column must have the same number
of elements as there are rows in the data.frame
.
In our survey dataset, the species are represented by a 2-letter code (e.g.,
"AB"), however, we would like to include the species name. The correspondance
between the 2 letter code and the names are in the file species.csv
. In this
file, one column includes the genus and another includes the species. First, we
are going to import this file in memory:
species <- read.csv("data/species.csv", stringsAsFactors=FALSE)
We are then going to use the function match()
to create a vector that contains
the genus names for all our observations. The function match()
takes at least
2 arguments: the values to be matched (in our case the 2 letter code from the
surveys
data frame held in the column species
), and the table that contains
the values to be matched against (in our case the 2 letter code in the species
data frame held in the column species_id
). The function returns the position
of the matches in the table, and this can be used to retrieve the genus names:
surveys_spid_index <- match(surveys$species_id, species$species_id)
surveys_genera <- species$genus[surveys_spid_index]
Now that we have our vector of genus names, we can add it as a new column to our
surveys
object:
surveys <- cbind(surveys, genus=surveys_genera)
-
Use the same approach to also include the species names in the
surveys
data frame. -
Use the help in R to understand what the function
paste()
does. Use it to add a new column calledgenus_species
into thespecies
data.frame
. -
Use the help to understand what the function
merge()
does. Use it to create a newdata.frame
that combines the content ofsurveys
and the modified version ofspecies
. -
Use this data set to answer the following:
- How many birds have been captured?
- How many individuals of the genus Dipodomys have been captured?
Let's create a data.frame
that contains the information only for the species
"DO" and "DM". We know how to create the data set for each species with the
function subset()
:
surveys_DO <- subset(surveys, species == "DO")
surveys_DM <- subset(surveys, species == "DM")
Similarly to cbind()
for columns, there is a function rbind()
(__r__ow
bind) that puts together two data.frame
. With rbind()
the number of
columns and their names must be identical between the two objects:
surveys_DO_DM <- rbind(surveys_DO, surveys_DM)
-
Using a similar approach, construct a new
data.frame
that only includes data for the years 2000 and 2001. -
How does it differ from
subset(surveys, species == "DO" | species == "DM")
?
Just like you can select columns by their positions in the data.frame
or by
their names, you can remove them similarly.
To remove it by column number:
surveys_noDate <- surveys[, -c(3:5)]
colnames(surveys)
## [1] "X" "record_id" "month" "day"
## [5] "year" "plot" "species_id" "sex"
## [9] "wgt" "genus" "species_name"
colnames(surveys_noDate)
## [1] "X" "record_id" "plot" "species_id"
## [5] "sex" "wgt" "genus" "species_name"
The easiest way to remove by name is to use the subset()
function. This time
we need to specify explicitly the argument select
as the default is to subset
on rows (as above). The minus sign indicates the names of the columns to remove
(note that the column names should not be quoted):
surveys_noDate2 <- subset(surveys, select=-c(month, day, year))
colnames(surveys_noDate2)
## [1] "X" "record_id" "plot" "species_id"
## [5] "sex" "wgt" "genus" "species_name"