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ser222_exam1_practice.lyx
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SER 222
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Practice
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Exam 1
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(SOLN)
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Updated 3/30/2024
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$
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Last 4 digits of ASU ID:
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$
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Exam Instructions
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The exam is open one note card (3x5 inches).
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Programming questions:
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Topic
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Earned
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Possible
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MC/SA: Data Abstraction
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15
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MC/SA: Stacks, Lists, and Generics
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10
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MC/SA: Analysis of Algorithms
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10
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MC/SA: Analysis, Design, and Justification I
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15
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Prog: Stacks, Lists, and Generics
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25
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Total:
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75
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Short Answer: Data Abstraction
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\begin_layout Enumerate
When would it make the most sense for the Point2D class to use polar coordinates
for its internal representation? [5 points]
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status open
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from FA19 exam
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\begin_deeper
\begin_layout Enumerate
When fast trigonometry functions are available.
\end_layout
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When the polar coordinates accessor and mutator methods will be used most
often.
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ANS
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When the API provides both Cartesian and polar coordinate methods.
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\begin_layout Enumerate
It never ever matters!
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Given the following piece of code which of the following statements is correct?
[5 points]
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Abraham
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public interface Numbers {
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int count();
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}
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public interface Characters {
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int length();
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This code will not compile, because method count() in interface Numbers
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\begin_layout Enumerate
This code will not compile, because class NaturalNumbers must implement
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\begin_layout Enumerate
This code will not compile, because the same class cannot extend a class
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\begin_layout Enumerate
This code will compile without errors.
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ANS
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When it comes to functionality (not performance), is it important to know
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[10 points]
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Ans:
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No.
The point of an ADT is that it is an abstraction where the internal representat
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Short Answer: Stacks, Lists, and Generics
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Consider an implementation of unsorted singly linked list.
Suppose it has a representation with a head and a tail pointer, where head's
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Given this representation, which of the following operation cannot be implement
ed in O(1) time? [5 points]
\end_layout
\begin_deeper
\begin_layout Enumerate
Insertion before the head node of the linked list.
\end_layout
\begin_layout Enumerate
Insertion after the tail node of the linked list.
\end_layout
\begin_layout Enumerate
Deletion of the head node of the linked list.
\end_layout
\begin_layout Enumerate
Deletion of the tail node of the linked list.
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status collapsed
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ANS
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\begin_layout Enumerate
Assume that we are storing the ASU IDs of 50 students in a singly linked
list.
Due to a security breach, one entire node has been corrupted in the middle.
In this case, will all the 50 nodes still be accessible to us? [5 points]
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\begin_deeper
\begin_layout Enumerate
Yes - the Java garbage collector will delete the bad node from the list.
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Yes - although we do not have a previous reference, we can use the tail
reference.
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No – any nodes that follow the corrupted node will be inaccessible.
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No - the entire list will be lost and the data will be inaccessible.
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Short Answer: Analysis of Algorithms
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\begin_layout Enumerate
Consider the following growth function: [5 points]
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\begin_inset Formula $f_{1}(n)=100+10log(n)n^{2}+45n$
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What is the Big-Oh order of this function? You should provide a relatively
tight upper bound (e.g., not just
\begin_inset Formula $2^{n}$
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).
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\begin_inset Formula $O(n^{3})$
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\begin_inset Formula $O(n^{2}log(n))$
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\begin_inset Formula $O(nlog(n))$
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\begin_inset Formula $O(n^{2})$
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\begin_inset Formula $O(log(n))$
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Prove that your bound holds.
(Hint: the definition for Big-Oh is
\begin_inset Formula $𝑓(𝑛)=𝑂(𝑔(𝑛))$
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iff
\begin_inset Formula $|f(n)|≤𝑐|𝑔(𝑛)|$
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(for
\begin_inset Formula $n>x_{0}$
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, where
\begin_inset Formula $x_{0}$
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is a constant, and
\begin_inset Formula $c$
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is also a constant).
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