-
Notifications
You must be signed in to change notification settings - Fork 0
/
线性单元.py
39 lines (35 loc) · 1.35 KB
/
线性单元.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
#coding=utf-8
#线性单元,只是把感知器的激活函数换了
from perceptron import Perceptron
#定义激活函数f
f=lambda x:x
class LinearUnit(Perceptron):
def __init__(self,input_num):
Perceptron.__init__(self,input_num,f)
def get_training_dataset():
# 构建训练数据,输入向量列表,每一项是工作年限
input_vecs = [[5], [3], [8], [1.4], [10.1]]
# 期望的输出列表,月薪,注意要与输入一一对应
labels = [5500, 2300, 7600, 1800, 11400]
return input_vecs, labels
def train_linear_unit():
'''
使用数据训练线性单元
'''
# 创建感知器,输入参数的特征数为1(工作年限)
lu = LinearUnit(1)
# 训练,迭代10轮, 学习速率为0.01
input_vecs, labels = get_training_dataset()
lu.train(input_vecs, labels, 10, 0.01)
#返回训练好的线性单元
return lu
if __name__ == '__main__':
'''训练线性单元'''
linear_unit = train_linear_unit()
# 打印训练获得的权重
print linear_unit
# 测试
print 'Work 3.4 years, monthly salary = %.2f' % linear_unit.predict([3.4])
print 'Work 15 years, monthly salary = %.2f' % linear_unit.predict([15])
print 'Work 1.5 years, monthly salary = %.2f' % linear_unit.predict([1.5])
print 'Work 6.3 years, monthly salary = %.2f' % linear_unit.predict([6.3])