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error in login process #9
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you error message " You visit our service very often. " ip blocked probably |
@tolgatasci i also tried using this API today, it is saying same for me "Hizmetimizi çok sık ziyaret ediyorsunuz." i have never used tiktok on my current IP |
change device |
I am sure my ip just try 2~3 times and my network public IP is dynamic which will change every day. I think it is not possible block by ip issue. I also change device id(get my mobile phone ), and change iid (get from tiktok url). But error message is same... so sad. :( |
Device_id openuid short New Device info insert Please
Andy Chiang <[email protected]>, 25 Şub 2019 Pzt, 06:52 tarihinde
şunu yazdı:
… I am sure my ip just try 2~3 times and my network public IP is dynamic
which will change every day. I think it is not possible block by ip issue.
I also change device id(get my mobile phone ), and change iid (get from
tiktok url). But error message is same... so sad. :(
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İyi çalışmalar dilerim.
TOLGA TAŞÇI
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after I use proxy app to get relevant data and update helper.py default default_veriable and use my own account data to login. I also use api.register to create new and I use name as a username to login but it is still not working. So how to give right username? |
@chiangandy how did you bypass |
@sukhcha-in use I describe, I use proxy app to get tiktok socket data, and modify parameter in helper.py default_veriable function and use below statement. |
I am also having the same issue. In the login I am getting same error message |
Thanks for your code sharing, it is helpful for me very much.
my testing is almost ok on 'no seesion required'.
But when I try login process, I got error message as below:
{'data': {'captcha': '', 'description': 'Hizmetimizi çok sık ziyaret ediyorsunuz.', 'error_code': 7}, 'message': 'error'}
I just simply input my tik tok account in demo.py, like...
api = api()
Do I need to do anything for this? Do I need to change device_id ,iid and openudid?
Your opinion will be appreciated. Thanks
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