forked from shuboc/LeetCode-2
-
Notifications
You must be signed in to change notification settings - Fork 0
/
basic-calculator-iii.py
72 lines (65 loc) · 2.13 KB
/
basic-calculator-iii.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
# Time: O(n)
# Space: O(n)
# Implement a basic calculator to evaluate a simple expression string.
#
# The expression string may contain open ( and closing parentheses ),
# the plus + or minus sign -, non-negative integers and empty spaces .
#
# The expression string contains only non-negative integers, +, -, *, /
# operators ,
# open ( and closing parentheses ) and empty spaces .
# The integer division should truncate toward zero.
#
# You may assume that the given expression is always valid.
#
# Some examples:
#
# "1 + 1" = 2
# " 6-4 / 2 " = 4
# "2*(5+5*2)/3+(6/2+8)" = 21
# "(2+6* 3+5- (3*14/7+2)*5)+3"=-12
#
# Note: Do not use the eval built-in library function.
try:
xrange # Python 2
except NameError:
xrange = range # Python 3
class Solution(object):
def calculate(self, s):
"""
:type s: str
:rtype: int
"""
operands, operators = [], []
operand = ""
for i in reversed(xrange(len(s))):
if s[i].isdigit():
operand += s[i]
if i == 0 or not s[i-1].isdigit():
operands.append(int(operand[::-1]))
operand = ""
elif s[i] == ')' or s[i] == '*' or s[i] == '/':
operators.append(s[i])
elif s[i] == '+' or s[i] == '-':
while operators and \
(operators[-1] == '*' or operators[-1] == '/'):
self.compute(operands, operators)
operators.append(s[i])
elif s[i] == '(':
while operators[-1] != ')':
self.compute(operands, operators)
operators.pop()
while operators:
self.compute(operands, operators)
return operands[-1]
def compute(self, operands, operators):
left, right = operands.pop(), operands.pop()
op = operators.pop()
if op == '+':
operands.append(left + right)
elif op == '-':
operands.append(left - right)
elif op == '*':
operands.append(left * right)
elif op == '/':
operands.append(left / right)