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fair-candy-swap.py
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fair-candy-swap.py
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# Time: O(m + n)
# Space: O(m + n)
# Alice and Bob have candy bars of different sizes:
# A[i] is the size of the i-th bar of candy that Alice has,
# and B[j] is the size of the j-th bar of candy that Bob has.
#
# Since they are friends,
# they would like to exchange one candy bar each so that after the exchange,
# they both have the same total amount of candy.
# (The total amount of candy a person has is
# the sum of the sizes of candy bars they have.)
#
# Return an integer array ans where ans[0] is the size of the candy bar
# that Alice must exchange,
# and ans[1] is the size of the candy bar that Bob must exchange.
#
# If there are multiple answers, you may return any one of them.
# It is guaranteed an answer exists.
#
# Example 1:
#
# Input: A = [1,1], B = [2,2]
# Output: [1,2]
# Example 2:
#
# Input: A = [1,2], B = [2,3]
# Output: [1,2]
# Example 3:
#
# Input: A = [2], B = [1,3]
# Output: [2,3]
# Example 4:
#
# Input: A = [1,2,5], B = [2,4]
# Output: [5,4]
#
# Note:
# - 1 <= A.length <= 10000
# - 1 <= B.length <= 10000
# - 1 <= A[i] <= 100000
# - 1 <= B[i] <= 100000
# - It is guaranteed that Alice and Bob have different total amounts of candy.
# - It is guaranteed there exists an answer.
class Solution(object):
def fairCandySwap(self, A, B):
"""
:type A: List[int]
:type B: List[int]
:rtype: List[int]
"""
diff = (sum(A)-sum(B))//2
setA = set(A)
for b in set(B):
if diff+b in setA:
return [diff+b, b]
return []