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main.cpp
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main.cpp
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/* 基于智能指针实现双向链表 */
#include <cstdio>
#include <memory>
struct Node {
// 这两个指针会造成什么问题?请修复
std::unique_ptr<Node> next;
Node* prev;
// 如果能改成 unique_ptr 就更好了!
int value;
// 这个构造函数有什么可以改进的?
explicit Node(int val) : value(val), prev(nullptr) {}
void insert(int val) {
auto node = std::make_unique<Node>(val);
node->next = std::move(next);
node->prev = prev;
if (next)
next->prev = node.get();
if (prev) {
prev->next = std::move(node);
}
}
void erase() {
if (next)
next->prev = prev;
if (prev)
prev->next = std::move(next);
}
~Node() {
printf("~Node()\n"); // 应输出多少次?为什么少了?应输出构造Node的次数,因为next和prev都是shared_ptr,会造成循环引用
}
};
struct List {
std::unique_ptr<Node> head;
List() = default;
List(List const &other) {
printf("List 被拷贝!\n");
// 请实现拷贝构造函数为 **深拷贝**
if (other.head == nullptr) {
head = nullptr;
return;
}
head = std::make_unique<Node>(other.head->value);
Node* curr1 = head.get();
Node* curr2 = other.head->next.get();
while (curr2) {
curr1->next = std::make_unique<Node>(curr2->value);
curr1->next->prev = curr1;
curr1 = curr1->next.get();
curr2 = curr2->next.get();
}
}
List &operator=(List const &) = delete; // 为什么删除拷贝赋值函数也不出错?
// 因为代码中List b = a只会调用拷贝构造函数,不会调用拷贝赋值函数
List(List &&) = default;
List &operator=(List &&) = default;
Node *front() const {
return head.get();
}
int pop_front() {
int ret = head->value;
head = std::move(head->next);
return ret;
}
void push_front(int value) {
auto node = std::make_unique<Node>(value);
if (head)
head->prev = node.get();
node->next = std::move(head);
head = std::move(node);
}
Node *at(size_t index) const {
auto curr = front();
for (size_t i = 0; i < index; i++) {
curr = curr->next.get();
}
return curr;
}
};
void print(const List& lst) { // 有什么值得改进的?改成传递const引用,避免复制和意外修改
printf("[");
for (auto curr = lst.front(); curr; curr = curr->next.get()) {
printf(" %d", curr->value);
}
printf(" ]\n");
}
int main() {
List a;
a.push_front(7);
a.push_front(5);
a.push_front(8);
a.push_front(2);
a.push_front(9);
a.push_front(4);
a.push_front(1);
print(a); // [ 1 4 9 2 8 5 7 ]
a.at(2)->erase();
print(a); // [ 1 4 2 8 5 7 ]
List b = a;
a.at(3)->erase();
print(a); // [ 1 4 2 5 7 ]
print(b); // [ 1 4 2 8 5 7 ]
b = {};
a = {};
return 0;
}