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scissors: laurel O #26

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30 changes: 24 additions & 6 deletions graphs/possible_bipartition.py
Original file line number Diff line number Diff line change
@@ -1,12 +1,30 @@
# Can be used for BFS
from collections import deque

def possible_bipartition(dislikes):
""" Will return True or False if the given graph
can be bipartitioned without neighboring nodes put
into the same partition.
Time Complexity: ?
Space Complexity: ?
Time Complexity: O(n)
Space Complexity: O(n)
DFS
"""

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👍 Really interesting DFS solution.

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@lolkinetzky lolkinetzky Feb 4, 2022

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谢谢您!
I had the help of your feedback over the previous messy DFS I'd worked through. Thank you for pushing me to think about how to use the adjacency list or graph structure more, and also, how python can make things nicer sometimes.

pass
dogs = len(dislikes)
if dogs == 0:
return True
graph = {dog:dislikes[dog] for dog in range(0,len(dislikes))}
sets_visited = [None]*(dogs)

for i in range(dogs):

if sets_visited[i] == None:
if not search(graph, sets_visited, i, True): return False

return True

def search(graph, sets, vertex, set):

if sets[vertex] == None:
sets[vertex] = set
return all(search(graph, sets, neighbor, not set) for neighbor in graph[vertex])

return sets[vertex] == set