Rock - Viri Vázquez #25
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CheezItMan
reviewed
Jan 11, 2022
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| def heap_sort(list): | ||
| """ This method uses a heap to sort an array. | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| """ |
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| def add(self, key, value = None): | ||
| """ This method adds a HeapNode instance to the heap | ||
| If value == None the new node's value should be set to key | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: O(log n) | ||
| Space Complexity: O(n) | ||
| """ |
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👍 However the space complexity is O(log n) due to the recursive call stack.
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| def remove(self): | ||
| """ This method removes and returns an element from the heap | ||
| maintaining the heap structure | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: O(log n) | ||
| Space Complexity: O(1) | ||
| """ |
There was a problem hiding this comment.
👍 However the space complexity is O(log n) due to the recursive call stack.
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| if len(self.store): | ||
| return False | ||
| return True |
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Suggested change
| if len(self.store): | |
| return False | |
| return True | |
| return len(self.store) |
| pass | ||
| if len(self.store): | ||
| return False | ||
| return True | ||
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| def heap_up(self, index): |
There was a problem hiding this comment.
👍 However the space complexity is O(log n) due to the recursive call stack.
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| if index and (self.store[index].key < self.store[parentNodeIdx].key): | ||
| self.swap(index, parentNodeIdx) | ||
| self.heap_up(parentNodeIdx) | ||
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| def heap_down(self, index): |
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Heaps Practice
Congratulations! You're submitting your assignment!
Comprehension Questions
heap_up&heap_downmethods useful? Why?