Even in the face of urllib.error.HTTPError, return the json

Previously, if we caught a urllib.error.HTTPError, we would try to
parse the json response. If we succeeded we would return _only_ the
`message` field of that response. If we failed, we're return the text
of the response.  By "return" here, I actually mean "pack up into an
Exception object and throw it".

Now, if succeed in parsing the response as json, we extend that
exception object so that it also contains the JSON that we got. That
way, client code can find extra goodies in the json["data"] field.

algosdk/error.py

@@ -178,9 +178,10 @@ def __init__(self, msg):
 
 
 class AlgodHTTPError(Exception):
-    def __init__(self, msg, code=None):
+    def __init__(self, msg, code=None, j=None):
         super().__init__(msg)
         self.code = code
+        self.json = j
 
 
 class AlgodResponseError(Exception):

algosdk/v2client/algod.py

@@ -105,10 +105,13 @@ def algod_request(
         except urllib.error.HTTPError as e:
             code = e.code
             es = e.read().decode("utf-8")
+            m = e  # If json.loads() fails, we'll return e itself
+            j = None
             try:
-                e = json.loads(es)["message"]
+                j = json.loads(es)
+                m = j["message"]
             finally:
-                raise error.AlgodHTTPError(e, code)
+                raise error.AlgodHTTPError(m, code, j)
         if response_format == "json":
             try:
                 return json.load(resp)