Skip to content

Commit

Permalink
BabyRudin: Solution: Ex15 in Ch02
Browse files Browse the repository at this point in the history
  • Loading branch information
ceciliachan1979 committed Jan 9, 2024
1 parent e1d1ea7 commit 3e90714
Showing 1 changed file with 13 additions and 0 deletions.
13 changes: 13 additions & 0 deletions Books/BabyRudin/Chapter02/ex15.tex
Original file line number Diff line number Diff line change
@@ -0,0 +1,13 @@
\subsection*{Exercise 15}
To show that the theorem is not true for closed subsets, consider the family of set $ \overline{\{n\}} $ for $ n \in \mathbb{N} $ as subsets of the real number line.

All the sets are closed because these isolated points have no additional limit points. (i.e any points that is not a natural number will have a neighborhood that does not intersect with the set.)
Any finite intersection is not empty there is a maximum number that is being deleted by the sets, and the number after it is not deleted by any set and therefore belong to the intersection.
But the infinite intersection is empty because there is no maximum number that is not deleted by any set.

To show that the theorem is not true for bounded subsets, consider the family of set $ [1, 2] $ with $ r $ deleted for all real numbers $ r $.

All the sets are bounded because they are all subsets of $ [1, 2] $.
Any finite intersection is not empty because there are infinitely many real numbers in $ [1, 2] $ but we only deleted a finite number of them, so there must be a number that is not deleted.
But the infinite intersection is empty because we deleted all the real numbers in $ [1, 2] $.

0 comments on commit 3e90714

Please sign in to comment.