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BabyRudin: Solution: Ex05 in Ch01
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gapry committed Jan 29, 2024
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\subsection*{Exercise 05 (Gapry)}
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$\text{(1) } \exists\ \alpha \in R \ni x \geq \alpha \ \forall x \in A$ \\
$\text{(2) } \exists\ \alpha \in R \ni -x \leq -\alpha \ \forall -x \in -A$ \\
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(1) $\implies \alpha = \inf( A)$ \\
(2) $\implies -\alpha = \sup(-A)$
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Obviously, $a = -(-a) \implies \inf(A) = -\sup(-A)$
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