-
Notifications
You must be signed in to change notification settings - Fork 4
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
- Loading branch information
1 parent
5efdbc1
commit d2c34fa
Showing
1 changed file
with
13 additions
and
0 deletions.
There are no files selected for viewing
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,13 @@ | ||
\subsection*{Exercise 15 (Cecilia)} | ||
To show that the theorem is not true for closed subsets, consider the family of set $ \overline{\{n\}} $ for $ n \in \mathbb{N} $ as subsets of the real number line. | ||
|
||
All the sets are closed because these isolated points have no additional limit points. (i.e any points that is not a natural number will have a neighborhood that does not intersect with the set.) | ||
Any finite intersection is not empty there is a maximum number that is being deleted by the sets, and the number after it is not deleted by any set and therefore belong to the intersection. | ||
But the infinite intersection is empty because there is no maximum number that is not deleted by any set. | ||
|
||
To show that the theorem is not true for bounded subsets, consider the family of set $ [1, 2] $ with $ r $ deleted for all real numbers $ r $. | ||
|
||
All the sets are bounded because they are all subsets of $ [1, 2] $. | ||
Any finite intersection is not empty because there are infinitely many real numbers in $ [1, 2] $ but we only deleted a finite number of them, so there must be a number that is not deleted. | ||
But the infinite intersection is empty because we deleted all the real numbers in $ [1, 2] $. | ||
|