Access values inside RxJS Observables as if they were directly available on the stream!
stream.pipe(pluck('msg')).subscribe(β¦);
// turn β into β
stream.msg.subscribe(β¦);
With good TypeScript support! π² Roughly speaking:
proxify( Observable<{ msg: string }> ) β Observable<{ msg: string }> & { msg: Observable<string> }
But recursively. So stream.msg
is a Proxy itself, allowing you to stream.msg.length.subscribe(β¦)
!
Proxify lets you access Observable API as well as pluck props and call methods at any depth of an Observable, Subject, or BehaviorSubject! See the API and Examples sections to learn more.
npm i rxjs-proxify
or try it online!
There are two methods available to you: proxify
and statify
proxify(stream)
will wrap your Observable, Subject or BehaviorSubject in a Proxy:
Observable Proxy
subscribe at any depth
const observable = proxify( of({ p: 'π' }) );
observable.subscribe(console.log); // > { p: π }
observable.p.subscribe(console.log); // > π
Subject Proxy
subscribe at any depth, push at the root
const subject = proxify(new Subject<{ p: string }>());
subject.subscribe(console.log);
subject.p.subscribe(console.log);
subject.next({ p: 'π₯' }); // > { p: π₯ } // > π₯
BehaviorSubject Proxy
subscribe at any depth, push at any depth, synchronously read the current state
const behavior = proxify(new BehaviorSubject({ p: 'π' }));
behavior.p.subscribe(console.log); // > π
behavior.p.next('π'); // > π
console.log(behavior.p.value) // > π
statify(value)
will put the value in a BehaviorSubject Proxy and add a distinctUntilChanged
operator on each property access.
State Proxy
subscribe to distinct updates at any depth, push at any depth, synchronously read the current state
// create a state
const state = statify({ a: 'π°', z: 'π‘' });
// listen to & log root state changes
state.subscribe(console.log); //> { a:π° z:π‘ }
// update particular substate
state.a.next('π'); //> { a:π z:π‘ }
// read current values
console.log(state.z.value + state.a.value); //> π‘π
// update root state, still logging
state.next({ a: 'π', z: 'βοΈ' }) //> { a:π z:βοΈ }
// and thenβ¦
state.z.next('π'); //> { a:π z:π }
state.a.next('ππ'); //> { a:ππ z:π }
state.z.next('πΈ') //> { a:ππ z:πΈ }
state.a.next('π¨'); //> { a:π¨ z:πΈ }
See Examples section for more details.
import { proxify } from "rxjs-proxify";
import { of } from "rxjs";
const o = of({ msg: 'Hello' }, { msg: 'World' });
const p = proxify(o);
p.msg.subscribe(console.log);
// equivalent to
// o.pipe(pluck('msg')).subscribe(console.log);
Convenient stream props splitting
import { proxify } from "rxjs-proxify";
import { of } from "rxjs";
const o = of({ msg: 'Hello', status: 'ok' }, { msg: 'World', status: 'ok' });
const { msg, status } = proxify(o);
msg.subscribe(console.log);
status.subscribe(console.log);
// equivalent to
// const msg = o.pipe(pluck('msg'));
// const status = o.pipe(pluck('status'));
// msg.subscribe(console.log);
// status.subscribe(console.log);
proxify
, e.g. with shareReplay
:
const { msg, status } = proxify(o.pipe(shareReplay(1)));
Concatenate all messages using pipe
with scan
operator:
import { proxify } from "rxjs-proxify";
import { of } from "rxjs";
import { scan } from "rxjs/operators";
const o = of({ msg: 'Hello' }, { msg: 'World' });
const p = proxify(o);
p.msg.pipe(scan((a,c)=> a + c)).subscribe(console.log);
// equivalent to
// o.pipe(pluck('msg'), scan((a,c)=> a + c)).subscribe(console.log);
Pick a method and call it:
import { proxify } from "rxjs-proxify";
import { of } from "rxjs";
const o = of({ msg: () => 'Hello' }, { msg: () => 'World' });
const p = proxify(o);
p.msg().subscribe(console.log);
// equivalent to
// o.pipe(map(x => x?.map())).subscribe(console.log);
Proxify is recursive, so you can keep chaining props or indices
import { proxify } from "rxjs-proxify";
import { of } from "rxjs";
const o = of({ msg: () => ['Hello'] }, { msg: () => ['World'] });
const p = proxify(o);
p.msg()[0].subscribe(console.log);
// equivalent to
// o.pipe(map(x => x?.map()), pluck(0)).subscribe(console.log);
That will be awesome!
Please create an issue before submiting a PR β we'll be able to discuss it first!
Thanks!