-
Notifications
You must be signed in to change notification settings - Fork 2.4k
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Solution #2184
base: master
Are you sure you want to change the base?
Solution #2184
Conversation
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Great job on implementing the formatDate
function! 🎉 Your solution meets the task requirements and constraints effectively. The function handles date conversion and formatting as expected, including the conversion between 2-digit and 4-digit years. While there are a couple of minor points regarding the use of fixed indices for separators in the join
and split
methods, these do not critically impact the functionality. Keep up the good work, and consider dynamically determining the separator for future improvements. Well done! 😊
✨ Please rate this review in the Platform's notification center. I will be grateful for your feedback! ✨
src/formatDate.js
Outdated
@@ -8,7 +8,25 @@ | |||
* @returns {string} | |||
*/ | |||
function formatDate(date, fromFormat, toFormat) { | |||
// write code here | |||
const dateParts = date.split(fromFormat[3]); |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
The split
method uses fromFormat[3]
as the delimiter, assuming the separator is always at this index. This might not be correct if the format array doesn't have a separator at index 3. Consider dynamically determining the separator based on the format string.
src/formatDate.js
Outdated
result[toFormat.indexOf('YYYY')] = year; | ||
} | ||
|
||
return result.join(toFormat[3]); |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
The join
method uses toFormat[3]
as the separator, assuming the separator is always at this index. This might not be correct if the format array doesn't have a separator at index 3. Consider dynamically determining the separator based on the format string.
No description provided.