Fix default behavior of literalEqual: #17467
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Do not share literals by default.
Instead, do it if users explicitly request so in their implementation of literalEqual:
Add tests
Fixes #17264
=> the reason is that reflectivity pushes AST nodes to the literal frame, and literal nodes are consireded equal if they have the same contents (regarless of their position in the tree). Thus, two similar nodes in different part of the trees were considered equals and shared, avoiding reflectivity to call the right method on the right node.