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Update docusaurus/docs/protocol/primitives/probabilistic_proofs.md
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Co-authored-by: Bryan White <[email protected]>
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Olshansk and bryanchriswhite authored Dec 17, 2024
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Expand Up @@ -214,6 +214,7 @@ $$ P(X = k+1) = q^k \cdot p $$

$$ E[K] = \frac{q}{p} $$

:::note
Recall:

- **Success**: The network **does** catch a dishonest Supplier
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