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Implement a list method #30
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arolett2
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,43 @@ | ||
// Copyright 2013 Google Inc. All Rights Reserved. | ||
// | ||
// Licensed under the Apache License, Version 2.0 (the "License"); | ||
// you may not use this file except in compliance with the License. | ||
// You may obtain a copy of the License at | ||
// | ||
// http://www.apache.org/licenses/LICENSE-2.0 | ||
// | ||
// Unless required by applicable law or agreed to in writing, software | ||
// distributed under the License is distributed on an "AS IS" BASIS, | ||
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
// See the License for the specific language governing permissions and | ||
// limitations under the License. | ||
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package drive | ||
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import ( | ||
"fmt" | ||
) | ||
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// List remote files if remote path exists. If path is a | ||
// directory, it recursively lists | ||
func (g *Commands) List() (err error) { | ||
var r *File | ||
if r, err = g.rem.FindByPath(g.opts.Path); err != nil { | ||
return | ||
} | ||
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if (!r.IsDir) { | ||
fmt.Println(r.Name) | ||
return | ||
} | ||
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var remoteChildren []*File | ||
if remoteChildren, err = g.rem.FindByParentId(r.Id); err != nil { | ||
return | ||
} | ||
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for _, rc := range remoteChildren { | ||
fmt.Println(rc.Name) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We may need to alter what we print out depending on the file MIME type, need to distinguish directories from regular files. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Sure. Makes sense I'll give that a shot. |
||
} | ||
return | ||
} |
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We need to do pagination on FindByParentId. It returns only the top 100 children.
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Thanks for taking a look! I implemented that in #24. Are you saying there is some additional work?