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[Tuple Set Dict Lab] Pedro Faria Blanc #227

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[Tuple Set Dict Lab] Pedro Faria Blanc #227

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197 changes: 169 additions & 28 deletions your-code/challenge-1.ipynb
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Original file line number Diff line number Diff line change
Expand Up @@ -15,11 +15,13 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 2,
"metadata": {},
"outputs": [],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"tup = (\"I\",)"
]
},
{
Expand All @@ -33,11 +35,24 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 3,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"tuple"
]
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"type(tup)"
]
},
{
Expand All @@ -55,13 +70,26 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 4,
"metadata": {},
"outputs": [],
"source": [
"# Your code here\n",
"\n",
"# Your explanation here\n"
"tup = [\"I\",]\n",
"tup.append(\"r\")\n",
"tup.append(\"o\")\n",
"tup.append(\"n\")\n",
"tup.append(\"h\")\n",
"tup.append(\"a\")\n",
"tup.append(\"c\")\n",
"tup.append(\"k\")\n",
"\n",
"\n",
"# Your explanation here\n",
"\n",
"#Tuples are immutable, which means their values cannot be changed after they are created.\n",
"#However, we can append one element at a time."
]
},
{
Expand All @@ -79,13 +107,15 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 5,
"metadata": {},
"outputs": [],
"source": [
"# Your code here\n",
"\n",
"# Your explanation here\n"
"# Your explanation here\n",
"\n",
"# Tuples are a data type which is actually immutable, this means that they cannot be changed once created."
]
},
{
Expand All @@ -103,11 +133,31 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 6,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"tup1: ('I', 'r', 'o', 'n')\n",
"tup2: ('h', 'a', 'c', 'k')\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"# define the tuple once again\n",
"tup = (\"I\", \"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k\")\n",
"\n",
"# since you can't use the method split() in tuples, reassign new variables called tup1 and tup2\n",
"tup1 = tup[:4]\n",
"tup2 = tup[-4:]\n",
"\n",
"# now print\n",
"print(\"tup1:\", tup1)\n",
"print(\"tup2:\", tup2)\n"
]
},
{
Expand All @@ -121,11 +171,26 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 7,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"tup3 and tup are equal\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"tup3 = tup1 + tup2\n",
"\n",
"tup3\n",
"\n",
"if tup3 == tup:\n",
" print(\"tup3 and tup are equal\")"
]
},
{
Expand All @@ -137,11 +202,33 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 8,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Number of elements in tup1: 4\n",
"Number of elements in tup2: 4\n",
"Number of elements in tup3: 8\n",
"True\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"count_tup1 = len(tup1)\n",
"count_tup2 = len(tup2)\n",
"count_tup3 = len(tup3)\n",
"\n",
"print(\"Number of elements in tup1:\", count_tup1)\n",
"print(\"Number of elements in tup2:\", count_tup2)\n",
"print(\"Number of elements in tup3:\", count_tup3)\n",
"\n",
"if count_tup1 + count_tup2 == count_tup3:\n",
" print(\"True\")"
]
},
{
Expand All @@ -153,11 +240,23 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 9,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"4\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"index_of_h = tup3.index(\"h\")\n",
"\n",
"print(index_of_h)"
]
},
{
Expand All @@ -177,11 +276,31 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 11,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"True\n",
"False\n",
"True\n",
"False\n",
"False\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"letters = [\"a\", \"b\", \"c\", \"d\", \"e\"]\n",
"\n",
"for letter in letters:\n",
" if letter in tup3:\n",
" print(True)\n",
" else:\n",
" print(False)"
]
},
{
Expand All @@ -195,11 +314,33 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 12,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The letter 'a' appears 1 time(s) in tup3\n",
"The letter 'b' appears 0 time(s) in tup3\n",
"The letter 'c' appears 1 time(s) in tup3\n",
"The letter 'd' appears 0 time(s) in tup3\n",
"The letter 'e' appears 0 time(s) in tup3\n"
]
}
],
"source": [
"# Your code here\n"
"# Your code here\n",
"\n",
"tup3 = (\"I\", \"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k\")\n",
"letters = [\"a\", \"b\", \"c\", \"d\", \"e\"]\n",
"\n",
"for letter in letters:\n",
" count = 0\n",
" for char in tup3:\n",
" if char == letter:\n",
" count += 1\n",
" print(f\"The letter '{letter}' appears {count} time(s) in tup3\")\n"
]
}
],
Expand All @@ -219,7 +360,7 @@
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.7.2"
"version": "3.11.2"
}
},
"nbformat": 4,
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