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internationalize word boundary checks #49
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Another way, based on https://stackoverflow.com/a/2998550:
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@@ -482,7 +457,7 @@ def extract_keywords(self, sentence, span_info=False): | |||
while idx < sentence_len: | |||
char = sentence[idx] | |||
# when we reach a character that might denote word end | |||
if char not in self.non_word_boundaries: | |||
if KeywordProcessor.NON_WORD_CHAR_REGEX.match(char): |
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why the ugly direct reference to the class? just use self
Another way to do it: from functools import lru_cache
from flashtext import KeywordProcessor
class NonWordBoundaries:
def __init__(self, *predicates):
self.predicates = predicates
@lru_cache(maxsize=128)
def __contains__(self, ch):
for predicate in self.predicates:
if predicate(ch):
return True
return False
def main():
words_to_search = ["рок"]
keyword_processor = KeywordProcessor()
keyword_processor.set_non_word_boundaries(NonWordBoundaries(str.isalpha, str.isdigit))
keyword_processor.add_keywords_from_list(words_to_search)
keywords_found = keyword_processor.extract_keywords('рок порок роковой')
print(keywords_found) Not sure about performance though. But at least it is easy to modify the behaviour. |
Benchmarks vs. Regex are for the English only char set. Is increasing the word boundaries like this effecting flashtext performance in any significant way? |
Hi there,
I think the only safe way to deal with issue #48 would be to test against the
\W
class [1]. Judging from the benchmarks linked on https://github.com/vi3k6i5/flashtext#why-not-regex this seems to run slower by a factor of 1-2 though.Best,
Alex
[1] Quoting the Python docs: