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heaps(sumitra, scissors class) #22
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Nice work Sumitra, you hit the learning goals here. Well done. I did leave some comments on space/time complexity. Let me know if you have questions.
def heap_sort(list): | ||
""" This method uses a heap to sort an array. | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(n log n) | ||
Space Complexity: O(n) | ||
""" |
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👍
return [] | ||
if len(list) == 1: | ||
return list |
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I don't think this is needed.
def add(self, key, value = None): | ||
""" This method adds a HeapNode instance to the heap | ||
If value == None the new node's value should be set to key | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(log n) | ||
Space Complexity: O(1) |
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👍 However the space complexity is O(log n) due to the recursive call stack.
def remove(self): | ||
""" This method removes and returns an element from the heap | ||
maintaining the heap structure | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(log n) | ||
Space Complexity: O(1) | ||
""" |
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👍 Similar issues with space complexity to the above.
if len(self.store) == 0: | ||
return True |
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if len(self.store) == 0: | |
return True | |
return len(self.store) == 0 |
""" | ||
pass | ||
if len(self.store) == 0: | ||
return True | ||
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def heap_up(self, index): |
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👍 However the space complexity is O(log n) due to the recursive call stack.
def heap_down(self, index): | ||
""" This helper method takes an index and | ||
moves the corresponding element down the heap if it's | ||
larger than either of its children and continues until | ||
the heap property is reestablished. | ||
""" |
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👍 However the space complexity is O(log n) due to the recursive call stack.
Heaps Practice
Congratulations! You're submitting your assignment!
Comprehension Questions
heap_up
&heap_down
methods useful? Why?