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heaps(sumitra, scissors class) #22
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Original file line number | Diff line number | Diff line change |
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@@ -1,8 +1,24 @@ | ||
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from heaps.min_heap import MinHeap | ||
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def heap_sort(list): | ||
""" This method uses a heap to sort an array. | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(n log n) | ||
Space Complexity: O(n) | ||
""" | ||
pass | ||
if not list: | ||
return [] | ||
if len(list) == 1: | ||
return list | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I don't think this is needed. |
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heap = MinHeap() | ||
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for item in list: | ||
heap.add(item) | ||
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sorted = [] | ||
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while heap.store: | ||
# print(sorted) | ||
sorted.append(heap.remove()) | ||
return sorted |
Original file line number | Diff line number | Diff line change | ||||||
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@@ -1,5 +1,4 @@ | ||||||||
class HeapNode: | ||||||||
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def __init__(self, key, value): | ||||||||
self.key = key | ||||||||
self.value = value | ||||||||
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@@ -21,21 +20,31 @@ def __init__(self): | |||||||
def add(self, key, value = None): | ||||||||
""" This method adds a HeapNode instance to the heap | ||||||||
If value == None the new node's value should be set to key | ||||||||
Time Complexity: ? | ||||||||
Space Complexity: ? | ||||||||
Time Complexity: O(log n) | ||||||||
Space Complexity: O(1) | ||||||||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However the space complexity is O(log n) due to the recursive call stack. |
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""" | ||||||||
pass | ||||||||
if value == None: | ||||||||
value = key | ||||||||
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node = HeapNode(key, value) | ||||||||
self.store.append(node) | ||||||||
self.heap_up(len(self.store) - 1) | ||||||||
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def remove(self): | ||||||||
""" This method removes and returns an element from the heap | ||||||||
maintaining the heap structure | ||||||||
Time Complexity: ? | ||||||||
Space Complexity: ? | ||||||||
Time Complexity: O(log n) | ||||||||
Space Complexity: O(1) | ||||||||
""" | ||||||||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 Similar issues with space complexity to the above. |
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pass | ||||||||
if len(self.store) == 0: | ||||||||
return None | ||||||||
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self.swap(0, len(self.store) - 1) | ||||||||
mini = self.store.pop() | ||||||||
self.heap_down(0) | ||||||||
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return mini.value | ||||||||
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def __str__(self): | ||||||||
""" This method lets you print the heap, when you're testing your app. | ||||||||
""" | ||||||||
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@@ -46,10 +55,11 @@ def __str__(self): | |||||||
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def empty(self): | ||||||||
""" This method returns true if the heap is empty | ||||||||
Time complexity: ? | ||||||||
Space complexity: ? | ||||||||
Time complexity: O(1) | ||||||||
Space complexity: O(1) | ||||||||
""" | ||||||||
pass | ||||||||
if len(self.store) == 0: | ||||||||
return True | ||||||||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more.
Suggested change
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def heap_up(self, index): | ||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However the space complexity is O(log n) due to the recursive call stack. |
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@@ -59,18 +69,39 @@ def heap_up(self, index): | |||||||
property is reestablished. | ||||||||
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This could be **very** helpful for the add method. | ||||||||
Time complexity: ? | ||||||||
Space complexity: ? | ||||||||
Time complexity: O(log n) | ||||||||
Space complexity: O(1) | ||||||||
""" | ||||||||
pass | ||||||||
if index == 0: | ||||||||
return index | ||||||||
parent_node = (index - 1) // 2 | ||||||||
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if self.store[parent_node].key > self.store[index].key: | ||||||||
self.swap(parent_node, index) | ||||||||
self.heap_up(parent_node) | ||||||||
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def heap_down(self, index): | ||||||||
""" This helper method takes an index and | ||||||||
moves the corresponding element down the heap if it's | ||||||||
larger than either of its children and continues until | ||||||||
the heap property is reestablished. | ||||||||
""" | ||||||||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However the space complexity is O(log n) due to the recursive call stack. |
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pass | ||||||||
current_size = self.store | ||||||||
left_child = index * 2 + 1 | ||||||||
right_child = index * 2 + 2 | ||||||||
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if left_child < len(current_size): | ||||||||
if right_child < len(current_size): | ||||||||
if current_size[left_child].key < current_size[right_child].key: | ||||||||
less = left_child | ||||||||
else: | ||||||||
less = right_child | ||||||||
else: | ||||||||
less = left_child | ||||||||
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if current_size[index].key > current_size[less].key: | ||||||||
self.swap(index, less) | ||||||||
self.heap_down(less) | ||||||||
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def swap(self, index_1, index_2): | ||||||||
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👍